What is the voltage drop for a three-phase, 3-wire, 240-volt circuit with a load of 5 HP located 110 ft away from the panel using No. 8 AWG copper THHN?

To determine the voltage drop for a three-phase, 3-wire, 240-volt circuit with a specified load and distance, it's essential to use the appropriate formulas that take into account the load in horsepower, distance, and wire gauge.

First, convert the horsepower to watts, as electrical calculations typically utilize watts. Since 1 HP is approximately 746 watts, a 5 HP load translates to around 3,730 watts (5 HP × 746).

Next, to determine the current (I) flowing through the circuit, we can utilize the formula for calculating current in a three-phase system:

[ I = \frac{P}{\sqrt{3} \times V} ]

Where P is power in watts and V is voltage. Plugging in our numbers gives:

[ I = \frac{3730}{\sqrt{3} \times 240} \approx 10.73 \text{ Amperes} ]

Now, the voltage drop can be calculated using the formula for a three-phase circuit:

[ \text{Voltage Drop (VD)} = \frac{1.732 \times I \times L \times R}{1000} ]

Where:

• 1.732 is